xpath解析爬取美女图片【★★】

By 大Van家 on 2021-07-23
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复习:XPath语法

需求:解析下载图片数据

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#!/usr/bin/env python 
# -*- coding:utf-8 -*-
# 需求:解析下载图片数据 http://pic.netbian.com/4kmeinv/
import requests
from lxml import etree
import os

if __name__ == "__main__":
url = 'http://pic.netbian.com/4kmeinv/'
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/89.0.4389.90 Safari/537.36'
}
response = requests.get(url=url, headers=headers)
# 手动设定响应数据的编码格式
# response.encoding = 'utf-8'
page_text = response.text

# 数据解析:src的属性值 alt属性
tree = etree.HTML(page_text)
li_list = tree.xpath('//div[@class="slist"]/ul/li')


# 创建一个文件夹
if not os.path.exists('./picLibs'):
os.mkdir('./picLibs')

for li in li_list:
img_src = 'http://pic.netbian.com'+li.xpath('./a/img/@src')[0]
img_name = li.xpath('./a/img/@alt')[0]+'.jpg'
# 通用处理中文乱码的解决方案
img_name = img_name.encode('iso-8859-1').decode('gbk')

# print(img_name,img_src)
# 请求图片进行持久化存储
img_data = requests.get(url=img_src, headers=headers).content
img_path = 'picLibs/'+img_name
with open(img_path, 'wb') as fp:
fp.write(img_data)
print(img_name, '下载成功!!!')

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